Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $5x^{2} - 4\sqrt{5}x + 4 = 0$.

(B) The given quadratic equation is $5x^{2} - 4\sqrt{5}x + 4 = 0$.
Comparing this with the standard form $ax^{2} + bx + c = 0$,we get $a = 5$,$b = -4\sqrt{5}$,and $c = 4$.
The discriminant $D$ is given by the formula $D = b^{2} - 4ac$.
Substituting the values,we get $D = (-4\sqrt{5})^{2} - 4(5)(4)$.
$D = (16 \times 5) - 80 = 80 - 80 = 0$.
Since the discriminant $D = 0$,the roots of the quadratic equation are real and equal.